2(3^x)+3/3^x=7

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Solution for 2(3^x)+3/3^x=7 equation: 



2(3^x)+3/3^x=7

We move all terms to the left:

2(3^x)+3/3^x-(7)=0



Domain of the equation: 3^x!=0

x!=0/1

x!=0

x∈R



We multiply all the terms by the denominator


23^x*3^x-7*3^x+3=0

Wy multiply elements

69x^2-21x+3=0

a = 69; b = -21; c = +3;
Δ = b2-4ac
Δ = -212-4·69·3
Δ = -387
Delta is less than zero, so there is no solution for the equation

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